50-5y-y^2=0

Solution for 50-5y-y^2=0 equation:

50-5y-y^2=0

We add all the numbers together, and all the variables

-1y^2-5y+50=0

a = -1; b = -5; c = +50;
Δ = b2-4ac
Δ = -52-4·(-1)·50
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-15}{2*-1}=\frac{-10}{-2}
=+5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+15}{2*-1}=\frac{20}{-2}
=-10
$